IIT JEE Advanced 2005 Maths Question Paper 1 Online
MCQ (Single Correct Answer)
Marks: +2, -0.5
Question:
The solution of primitive integral equation (x2 + y2)dy = xydx is y = y(x).
If y(1) = 1 and y(x0) = e, then x0 is equal to
Option A : √2(e2 – 1)
Option B : √2(e2 + 1)
Option C : √3e
Option D : √(e2 – 1)
Solution:
This question is asked in IIT JEE Advanced 2005 Screening Maths Questions Paper and it is from Differential Equations Chapter.
The solution of this question is as below.
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